#include<bits/stdc++.h>
using namespace std;
int main()
{
	long long n,m,k;
	cin>>n>>m>>k;
	long long n2=n-(k+(m-1))/m+1;
	long long n3=(k+(m-1))/m;
	long long m2=k%m;
	if(m2==0)
	{
		m2=3;
	}
	cout<<n3+(m2-1)<<" "<<n2+(m2-1)<<endl;
	return 0;
}